Headrick and Kowalchuk (2007) outlined a general method for comparing a simulated distribution \(\Large Y\) to a given theoretical distribution \(\Large Y^*\). Note that these could easily be modified for comparison to an empirical vector of data:
Obtain the standardized cumulants (skewness,
kurtosis, fifth, and sixth) for \(\Large
Y^*\). This can be done using calc_theory along with
either the distribution name (plus up to 4 parameters) or the pdf fx
(plus support bounds). In the case of an empirical vector of data, use
calc_moments or calc_fisherk.
Obtain the constants for \(\Large Y\). This can be done using
find_constants or by simulating the distribution with
nonnormvar1.
Determine whether these constants produce a valid power
method pdf. The results of find_constants or
nonnormvar1 indicate whether the constants yield an invalid
or valid pdf. The constants may also be checked using
pdf_check. If the constants generate an invalid pdf, the
user should check if the kurtosis falls above the lower bound (using
calc_lower_skurt). If yes, a vector of sixth cumulant
correction values should be used in find_constants or
nonnormvar1 to find the smallest correction that produces
valid pdf constants.
Select a critical value from \(\Large Y^*\), i.e. \(\Large y^*\) such that \(\Large Pr(Y^* \ge y^*) = \alpha\). This can
be done using the appropriate quantile function and \(\Large 1 - \alpha\) value
(i.e. qexp(1 - 0.05)).
Solve \(\Large m_{2}^{1/2} * p(z') + m_{1} - y^* = 0\) for \(\Large z'\), where \(\Large m_{1}\) and \(\Large m_{2}\) are the 1st and 2nd moments of \(\Large Y^*\).
Calculate \(\Large 1 - \Phi(z')\), the corresponding probability for the approximation \(\Large Y\) to \(\Large Y^*\) (i.e. \(\Large 1 - \Phi(z') = 0.05\)) and compare to the target value \(\Large \alpha\).
Plot a parametric graph of \(\Large Y^*\) and \(\Large Y\). This can be done with a set of
constants using plot_pdf_theory (overlay =
TRUE) or with a simulated vector of data using
plot_sim_pdf_theory (overlay = TRUE). If
comparing to an empirical vector of data, use plot_pdf_ext
or plot_sim_pdf_ext.
Use these steps to compare a simulated exponential(mean = 2)
variable to the theoretical exponential(mean = 2) density.
(Note that the printr package is invoked to display the
tables.)
In R, the exponential parameter is
rate <- 1/mean.
Note that calc_theory returns the standard deviation,
not the variance. The simulation functions require variance as the
input.
H_exp <- nonnormvar1("Polynomial", means = stcums[1], vars = stcums[2]^2,
skews = stcums[3], skurts = stcums[4],
fifths = stcums[5], sixths = stcums[6], n = 10000,
seed = 1234)## Constants: Distribution 1
##
## Constants calculation time: 0 minutes
## Total Simulation time: 0 minutes
Look at the power method constants.
| c0 | c1 | c2 | c3 | c4 | c5 |
|---|---|---|---|---|---|
| -0.3077396 | 0.8005605 | 0.318764 | 0.0335001 | -0.0036748 | 0.0001587 |
Look at a summary of the target distribution.
as.matrix(round(H_exp$summary_targetcont[, c("Distribution", "mean", "sd",
"skew", "skurtosis", "fifth",
"sixth")], 5), nrow = 1, ncol = 7,
byrow = TRUE)| Distribution | mean | sd | skew | skurtosis | fifth | sixth | |
|---|---|---|---|---|---|---|---|
| mean | 1 | 2 | 2 | 2 | 6 | 24 | 120 |
Compare to a summary of the simulated distribution.
as.matrix(round(H_exp$summary_continuous[, c("Distribution", "mean", "sd",
"skew", "skurtosis", "fifth",
"sixth")], 5), nrow = 1, ncol = 7,
byrow = TRUE)| Distribution | mean | sd | skew | skurtosis | fifth | sixth | |
|---|---|---|---|---|---|---|---|
| X1 | 1 | 1.99987 | 2.0024 | 2.03382 | 6.18067 | 23.74145 | 100.3358 |
Let \(\Large \alpha = 0.05\).
## [1] 5.991465
Since the exponential(2) distribution has a mean and standard deviation equal to 2, solve \(\Large 2 * p(z') + 2 - y_star = 0\) for \(\Large z'\). Here, \(\Large p(z') = c0 + c1 * z' + c2 * z'^2 + c3 * z'^3 + c4 * z'^4 + c5 * z'^5\).
f_exp <- function(z, c, y) {
return(2 * (c[1] + c[2] * z + c[3] * z^2 + c[4] * z^3 + c[5] * z^4 +
c[6] * z^5) + 2 - y)
}
z_prime <- uniroot(f_exp, interval = c(-1e06, 1e06),
c = as.numeric(H_exp$constants), y = y_star)$root
z_prime## [1] 1.644926
## [1] 0.04999249
This is approximately equal to the \(\Large \alpha\) value of 0.05, indicating the method provides a good approximation to the actual distribution.
We can also plot the empirical cdf and show the cumulative probability up to y_star.